10x^2+2x-44=0

Solution for 10x^2+2x-44=0 equation:

10x^2+2x-44=0

a = 10; b = 2; c = -44;
Δ = b2-4ac
Δ = 22-4·10·(-44)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-42}{2*10}=\frac{-44}{20}
=-2+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+42}{2*10}=\frac{40}{20}
=2
$